17 Replies
given method
ig these too could be the possible cases
@Apu
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.Triangle is easy. nC3 - number of ways choosing three collinear points
It doesn't match criteria of different sides tho innit?
Quadrilaterals, you can have at most two pairs which are collinear so id say go case wise.
hmmm
nC3 won't be here tho right?
Why?
Because it says "vertices from different sides"
Oh yeah nvm
nC3 would just count cases where 2 or 3 are from the same side
So it's basically a lot of addition
You need to go casewise
Yep.
Choose three sides, choose a point each
Rinse and Repeat
Quadrilateral is simpler. All four sides to choose are predefined. So just choose a point each.
i get it , thanks
@Opt could u go thru that migratory aptitude ques...