14 Replies
@Apu
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.AB = AC = radius = 4
one way is to solve circle and line but that will be lenghty can we proceed from here , i cant think further
just solve the line and the circle man
Why would that be lengthy? Minimum value occurs at perpendicular from (-1,0) while maximum would be the other extremity (C in the figure)
nothing you could do in situation
yeah but seedha line and circle ko solve karke point nikal ke distance nikal lena will be easier ig
(x+5)^2+y^2=4 and you have y=x+5. So y^2=2.
Or you could calculate the foot of perpendicular and the perpendicular distance
ye bhi theek hai
that would be kinda lengthy too but
Nah just saying the end which is further from foot of perpendicular
Will give maximum distance.
If the point is somewhere it is not easy to visualize which is further
Oh right my bad lol.
yeah i got that
im saying ki foot of perpendicular wala point nikaal lo line pe
and Find perpendicular distance on 1,0 from the line
Then Pythagoras
🐴lots of ways to go by this
True but the gist of everything is same.
yeah
its a calculative question
y=-sqrt(2) for the point we need. (-sqrt(2)-5,-sqrt(2)) is needed point.