Hydride shift (?)
why would carbocation not rearrange to give option (d)
(attatched my working)
8 Replies
Hello @manas!
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i believe its because of ngp im not sure of the mechanism
Is B the answer?
I assume that the H+ will attack on benzene first, then the cyclopropyl ring will neutralize the positive charge on benzene ring to form product in (B). It's a perfectly aromatic system if you see.
Benzene pe negative charge aayega (Ph- is still aromatic as this negative charge is localised and doesn't participate in resonance) and cyclopropenium cation is formed which is stable due to dancing resonance
sorted?^
yes sir, thank you
apolgogies to all those who replied for not checking earlier
Can you please close it out? Check the pinned thread in the doubts section on how to do so :)
+solved @Flame Tests Lover
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