I
iTeachChem•2mo ago
Gamertug

Curren Electricity

for this question i did E = V/l = IR/l E = I (rho)/A But answer is not comign that way
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20 Replies
iTeachChem Helper
iTeachChem Helper•2mo ago
@Gyro Gearloose
iTeachChem Helper
iTeachChem Helper•2mo ago
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.
Padmakar 🅴
Padmakar 🅴•2mo ago
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Dexter
Dexter•2mo ago
I = JA cos60 E = rhoJ
Gamertug
GamertugOP•2mo ago
why dint what i do work i did E = Icos60 Rho/ A and i am getting 2.5x11x10^-6?
Padmakar 🅴
Padmakar 🅴•2mo ago
calculation error bruv
Gamertug
GamertugOP•2mo ago
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Gamertug
GamertugOP•2mo ago
i am 99.99999% sure there is no calc error ,rotate
TeXit
TeXit•2mo ago
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Dexter
Dexter•2mo ago
J ka scene hoga na yaar seedha ohms law kaise laga do ge agar J is not in the direction of current if they hamper with the current density or drift velocity wagera then go to the Basic equations of current electricity dont use ohms law seedha seedhi
Gamertug
GamertugOP•2mo ago
wont doing cos60 be enough> which ones
Dexter
Dexter•2mo ago
Haan agar ye kiya hai to then answer aana chahiye I= neAvd E=rho J J =sigma E Vd =eEt/m ye sab jisko use krke ohms law derive kiya tha
Gamertug
GamertugOP•2mo ago
what are the below 3 i only know of first whats the last wait what E = rho J and J = sigma E what
Dexter
Dexter•2mo ago
Huh you don't know these formulas? E = rho J? Drift velocity ka formula last one nahi aata utna kaam but pehle 3 to important hai kaafi
Gamertug
GamertugOP•2mo ago
E = rho J then how is J = sigma E i will just ratta
Padmakar 🅴
Padmakar 🅴•2mo ago
You did a calculation error I cos 60 Nahiii, A cos 60 I is a scalar How will u get a component of a scalar For current, take areal vector in drxn of current not the other way around
Gamertug
GamertugOP•2mo ago
oh ok oh ye i got the ans
Padmakar 🅴
Padmakar 🅴•2mo ago
u'll get answer
Gamertug
GamertugOP•2mo ago
thx +solved @Padmakar 🅴 @Dexter
iTeachChem Helper
iTeachChem Helper•2mo ago
Post locked and archived successfully!
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