26 Replies
@Gyro Gearloose
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.it is a log scale
decibel ie
baaki dunno xD
I assume intensity is gonna die out by inverse square law.
Conservation of energy flux applies
this is from waves, but i dont think its in mains
since its nowhere in NCERT
yeah there is some conversion between intensity and decibels that i can't recall
That's fine. L = $log_{10}( \frac{I}{I_0})$
Opt
I_0 is what?
Reference intensity. Based on human ear.
It's given in the question anyways
acha acha
It's the part after that which is weird. Inverse square law is the only thing I can think of.
yeah the inverse square law makes perfect sense here
intensity = power / area, area being the surface area of sphere of influence of the sound (4pi*r^2)
i.e. intensity is inversely proportional to distance squared @Gamertug
try that and see
get intensity values using the decibel and intensity conversion above
I_0, which is reference intensity, is given as 20dB in the question
maximum distance of clear hearing would also be the point where the loudness is 20dB
I am getting 10¹⁰m which is def wrong 💀
It is also quite a large distance isn't it?
About 33 lightseconds.
answer is in meters 💀 🙏
wtf LMAO
Arrey, I'm guessing this one. Half volume ho raha hai. Chalo, 4m guess karein.
10^-12 ig
C?
@Gamertug
sound level ka formula is 10log(I/I°) actually
not just log(I/I°)
@Opt this is the solution ig
Oh I see. Yeah, that makes a hell of a difference when logs are involved.
fr
electrochem mein bhi yahi dikkat
antilog of decimal numbers are a pain
ic
still is this even there in jee mains
yes
Sound levels hai
@Gamertug if your doubt is solved please close it with tagging the helpers
+solved @Dexter @Opt
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