26 Replies
@Gyro Gearloose
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.Hmmm what was your approach
friction ka Work = Heat loss?
Oh. My. Lord.
iwas thinking abt relating the constant velocity to the melting of ice due to work done against friction and determining the rate of mass loss.
hmm weird sawaal hai tbh
😿ðŸ˜
...wtf is this question?
I can think of ways to make it worse, but damn.
coeff of fric?
for t to come 1.848 i need coeff of fric to come out as 0.0009199 💀
Mera bhai khuch thousand mai ara tha answer decimal mai hai :aah:
I will try again:sweaty:
Me Kal dungi solve krke
Bro you sure Itta hi diya info
:Saul_Goodman: because everyone is confuse
Yeh wala kal subah tak bhej dunga
Ping me at 6-7
I need to Revise Calorimetry
:hello:
I will send after 5 pm
Because I have 7 tests :Saul_Goodman:
Mein am ki baat kr raha 12 hours ahead
:Rick_cool_smug:
Could be 6pm too
Fast
@itsav23 coeff of fric telll
yep...bas yehi hai question
ans is given in seconds
dude nai pata mereko...not given
Bru then how can you calculate bruh
@itsav23 package ka hai?
constant velocity di toh hai
I tried par mew is still needed
umgcostheta = mgsintheta se u (mew) aa gya
const velocity means no ext force
Oh
Yes
I'm dumb
koi na..happens
sorted?
nah'
nah
work by friction + PE due to loss in height = 4.2 mL krde
Was the question written like this only or was it in a book or something in printed form?