Java Community | Help. Code. Learn.•3w ago

ID format issue as UUID String in Spring Boot with MongoDb

I created an example of Spring Boot with MongoDb. I have a problem in getting an entity by id with validation as it throws "must be a valid UUID". Here is the entity shown below

    @Getter
    @Setter
    @SuperBuilder
    @EqualsAndHashCode(callSuper = true)
    @NoArgsConstructor
    @AllArgsConstructor
    @Document(collection = "airport-collection")
    public class AirportEntity extends BaseEntity {
    
        @Id
        @Indexed(unique = true)
        @Field(name = "_id")
        private String id = UUID.randomUUID().toString();
    
        @Field(name = "AIRPORT_NAME")
        private String name;
    
        @Field(name = "CITY_NAME")
        private String cityName;
    
    }

    @Getter
    @Setter
    @SuperBuilder
    @EqualsAndHashCode(callSuper = true)
    @NoArgsConstructor
    @AllArgsConstructor
    @Document(collection = "airport-collection")
    public class AirportEntity extends BaseEntity {
    
        @Id
        @Indexed(unique = true)
        @Field(name = "_id")
        private String id = UUID.randomUUID().toString();
    
        @Field(name = "AIRPORT_NAME")
        private String name;
    
        @Field(name = "CITY_NAME")
        private String cityName;
    
    }

When I call getAirportById(@PathVariable @Valid @UUID final String id) from Controller like localhost:8080/api/v1/airports/6781972fa25a3e577395c444 , I got this issue shown below

{
    "time": "2025-01-11T00:55:27.5670908",
    "httpStatus": "BAD_REQUEST",
    "header": "VALIDATION ERROR",
    "message": "Constraint violation",
    "isSuccess": false,
    "subErrors": [
        {
            "message": "must be a valid UUID",
            "field": "id",
            "value": "6781972fa25a3e577395c444",
            "type": "String"
        }
    ]
}

{
    "time": "2025-01-11T00:55:27.5670908",
    "httpStatus": "BAD_REQUEST",
    "header": "VALIDATION ERROR",
    "message": "Constraint violation",
    "isSuccess": false,
    "subErrors": [
        {
            "message": "must be a valid UUID",
            "field": "id",
            "value": "6781972fa25a3e577395c444",
            "type": "String"
        }
    ]
}

Here is the value stored in the collection

    _id : ObjectId(6781972fa25a3e577395c444)
    AIRPORT_NAME : String
    CITY_NAME : String
    _class : Entity clas

    _id : ObjectId(6781972fa25a3e577395c444)
    AIRPORT_NAME : String
    CITY_NAME : String
    _class : Entity clas

How can I fix the issue?

61 Replies

JavaBot•3w ago

⌛ This post has been reserved for your question.

Hey @direct_x_34! Please use /close or the Close Post button above when your problem is solved. Please remember to follow the help guidelines. This post will be automatically marked as dormant after 300 minutes of inactivity.

TIP: Narrow down your issue to simple and precise questions to maximize the chance that others will reply in here.

dan1st•3w ago

Maybe you need to format it differently? for example 6781972f-a25a-3e577395c444 actually nvm I think that's too short 6781972fa25a3e577395c444 cannot be a valid UUID I think like MongoDB ids are 96bit while UUIDs are 128bit

direct_x_34OP•3w ago

@dan1st

@Id
        @Indexed(unique = true)
        @Field(name = "_id")
        private String id = UUID.randomUUID().toString();

@Id
        @Indexed(unique = true)
        @Field(name = "_id")
        private String id = UUID.randomUUID().toString();

I defined it here

dan1st•3w ago

@ And did you check whether the value stored in the DB/used as _id is actually the UUID you generated?

direct_x_34OP•3w ago

It is stored as _id : ObjectId(6781972fa25a3e577395c444) as I mentioned before.

dan1st•3w ago

Yeah and did UUID.randomUUID().toString() really return 6781972fa25a3e577395c444 for you?

direct_x_34OP•3w ago

Exactly.

dan1st•3w ago

How did you check?

direct_x_34OP•3w ago

I couldn't solve it.

dan1st•3w ago

What?

direct_x_34OP•3w ago

UUID.randomUUID().toString() -> 6781972fa25a3e577395c444

direct_x_34OP•3w ago

direct_x_34OP•3w ago

All _ids seems like that

dan1st•3w ago

What tells you that MongoDB didn't just overwrite thatto a different value?

direct_x_34OP•3w ago

Where is the problem in entity

dan1st•3w ago

UUID.randomUUID().toString() doesn't generate values like that - this is a value generated by MongoDB, not a UUID ObjectId(...) and UUID and completely different things

direct_x_34OP•3w ago

How can I revise it in the entity?

dan1st•3w ago

First, in the entity

        @Id
        @Indexed(unique = true)
        @Field(name = "_id")
        private String id = "";

        @Id
        @Indexed(unique = true)
        @Field(name = "_id")
        private String id = "";

or whatever, the UUID generation is pointless Secondly to fix the error: change the @PathVariable @Valid @UUID final String id to @PathVariable @Valid final String id

direct_x_34OP•3w ago

It should be UUID

dan1st•3w ago

it isn't _id cannot be a UUID MongoDB doesn't allow that AFAIK if you want a UUID, you'd need another field

direct_x_34OP•3w ago

How can I revise it?

dan1st•3w ago

revise what?

direct_x_34OP•3w ago

I use UUID for id as I said before.

dan1st•3w ago

you have two options: - don't use UUIDs - use UUIDs but not in _id (so you have an ObjectId and a UUID in different fields) tertium non dator

direct_x_34OP•3w ago

I want to use id as UUID

dan1st•3w ago

Why do you even have the idea that this would be possible? well it might e possible if you don't use ObjectId

direct_x_34OP•3w ago

How can I use id as UUID string format? Is it possible to define it inside the entity?

dan1st•3w ago

https://www.baeldung.com/java-mongodb-uuid

Baeldung

UUID as Entity ID in MongoDB | Baeldung

Learn to use a UUID as an entity ID in MongoDB.

direct_x_34OP•3w ago

I also asked ChatGpt but it couldn't provide the solutions I already looked through the link before.

dan1st•3w ago

Can you try not using String for the ID? but directly using UUID? like

        @Id
        @Indexed(unique = true)
        @Field(name = "_id")
        private String UUID id = UUID.randomUUID();

        @Id
        @Indexed(unique = true)
        @Field(name = "_id")
        private String UUID id = UUID.randomUUID();

and maybe also add spring.data.mongodb.uuid-representation=standard to your application.properties

direct_x_34OP•3w ago

It didn't help me fix the issue

dan1st•3w ago

What happens with it? Note that old documents won't work with that so consider using a new database

direct_x_34OP•3w ago

I already delected all collections from mongodb

dan1st•3w ago

Did you insert a new object first?

direct_x_34OP•3w ago

Yeah

direct_x_34OP•3w ago

dan1st•3w ago

What does it look like in MongoDB? How did you insert that object?

direct_x_34OP•3w ago

I did it

dan1st•3w ago

So your Java application inserted the object into the DB? Can you print the content of the id field before inserting? How do you get that JSON here?

direct_x_34OP•3w ago

Its id is 6781a12a22e4f962650b7fec. Not UUID even if I defined private String id = UUID.randomUUID().toString();

dan1st•3w ago

Can you show the code where you printed it in the Java application? before saving it and the code returning the response

direct_x_34OP•3w ago

id cannot perceive UUID as I said many times

dan1st•3w ago

I have no idea what you are talking about

direct_x_34OP•3w ago

I have no idea what you are talking about too. I already mentioned the problem about not inserting UUID string format id but you said different things

dan1st•3w ago

You have some code that inserts the object in the DB I asked you to include something printing the id field before that happens and show that code

ayylmao123xdd•3w ago

🎿 🐝 🦌 @direct_x_34 is it fixed now

JavaBot•3w ago

💤 Post marked as dormant

This post has been inactive for over 300 minutes, thus, it has been archived. If your question was not answered yet, feel free to re-open this post or create a new one. In case your post is not getting any attention, you can try to use /help ping. Warning: abusing this will result in moderative actions taken against you.

direct_x_34OP•3w ago

No @ayylmao123xdd

ayylmao123xdd•3w ago

can you show the validation for this uuid thing where it gave you the 'must be a valid uuid'

ayylmao123xdd•3w ago

but yea probably listen to daniel and read this article https://www.baeldung.com/java-mongodb-uuid

Baeldung

UUID as Entity ID in MongoDB | Baeldung

Learn to use a UUID as an entity ID in MongoDB.

dan1st•3w ago

ah I also linked to that before also they got an answer on SO and comments disagreeing with the answer (idk how trustworthy that comment is) actually a spam detection system got alerted about that answer but I marked it as a false positive

ayylmao123xdd•3w ago

well yea from what i saw the problem is that mongo doesnt hold ids that long so he needs to make a custom key generation shorter than uuid

dan1st•3w ago

that's what happens on SO: https://stackoverflow.com/a/79347990/10871900

Stack Overflow

ID format issue as UUID String in Spring Boot with MongoDb

I created an example of Spring Boot with MongoDb. I have a problem in getting an entity by id with validation as it throws "must be a valid UUID". Here is the entity shown below @Getter @...

ayylmao123xdd•3w ago

so he just put the invalid uuid in controller based on the comments It should be e58ed763-928c-4155-bee9-fdbaaadc15f3 as I defined private String id = UUID.randomUUID().toString(); so just gotta put this in controller instead of the shorter string

dan1st•3w ago

🤦

ayylmao123xdd•3w ago

:shrugging:

dan1st•3w ago

I'm not saying anything more

ayylmao123xdd•3w ago

disaster

JavaBot•3w ago

💤 Post marked as dormant

This post has been inactive for over 300 minutes, thus, it has been archived. If your question was not answered yet, feel free to re-open this post or create a new one. In case your post is not getting any attention, you can try to use /help ping. Warning: abusing this will result in moderative actions taken against you.

Gaming

Programming

ID format issue as UUID String in Spring Boot with MongoDb

Did you find this page helpful?