32 Replies
@Dexter
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.AlCl3 is a Lewis Acid, which means it takes the lone pair from the ether oxygen
That leaves the oxygen positively charged, so it breaks one of the bonds next to it and takes both the electrons to become neutral
However, that leaves (+)C=O
To make this more stable, the hydrogen from the carbon next to (+)C=O goes on there and creates a carbocation where it was
The positive charged compound, which is now an electrophile, then attacks benzene's pi electrons
I'm taking a guess here, try writing that down and tell me what you get
ok
something like this @Nimboi?
,rotate
yess
but ek carbon zyada pe lagaya hai tune carbonyl
,rotate
what did i do wrong , which step
last step i attacked on benzene
aare ketone wala group benzene ke just baad hoga
how
because +ve charge dekho kahan hai
it shifted
and fir usse attack karke bond banaega to bas ek hi bond aaega na
to secondary
😿idts shift hoga isme
why , it would be super unstable , +ve mai oxygen aur kich raha hai
but oxygen still has a lonepair
oxygen ka triple bond tho😶
seems shady
yes it will also resonate if it shifts
let the others check
ok
How to find major aldol product in this reaction?
Dibal H will reduce the cynide to Imine
Imine ke hydrolysis se Aldehyde
and Acetaldehyde and this aldehyde will do aldol
In cross aldol two products will be formed (option a and b)
which one should we take as major product
no?
ek hi product aaega
aromatic wale aldehyde mein There are no alpha H
how will you do aldol from that
that makes sense....Thanks a lot
+solved @Dexter
:( @nermal
Hmmmm
wait i’ll figure it out
+solved @Dexter
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