C#•2mo ago

return Object<byte> after checking typeof(T) == typeof(byte)

Is this possible or is there a way to sort of do this? I'm trying to do something like this:

if (typeof(TValue) == typeof(sbyte)) {
    return new MyObject<sbyte>(defaultValue, getValue, setValue, (x) => sbyte.Parse(x));
}

if (typeof(TValue) == typeof(sbyte)) {
    return new MyObject<sbyte>(defaultValue, getValue, setValue, (x) => sbyte.Parse(x));
}

6 Replies

bighugemassive3OP•2mo ago

Yeah The constructor takes Func<string, TValue> fromString That what I think i'll do, just use object instead of TValue

jcotton42•2mo ago

You can do (TValue)(object)val if (TValue)val doesn’t work. The JIT recognizes this pattern and will throw away the cast.

bighugemassive3OP•2mo ago

It's for a serialisable property I'm wondering if constrainting TValue to INumberBase<TValue> would work

jcotton42•2mo ago

Do you actually care if it’s a number, or just if it’s parseable?

bighugemassive3OP•2mo ago

Just parsable really where TValue : IParsable<TValue> seems to work though Though not sure if it works at runtime, i have way too many errors at the moment

paperClip•2mo ago

yet another generic bridging problem smh

Gaming

Programming

return Object<byte> after checking typeof(T) == typeof(byte)

Did you find this page helpful?