30 Replies
@Apu
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.question wants area of ABCDEF or the area of other two triangles combined ?
i got ar(ABCDEF) = 2e(a^2+b^2)
ans given is b^4/a(a^2-b^2)^1/2
area of triangles poocha hai
interesting
Wait a second, isn't there a direct formula for this?
If you have tangents to a conic from an external point, then the area of the triangle will be uhhh i forgot but it has (S_1)^(3/2) na?
idr anything like this
Thats jus for parabola
you need to know the external point for that
Yup yup. But that's pretty simple
I don't think so.
for external point it is (r.(s11)^3/2)/(sqrt(r^2+s11)
Oh, there's an r
So circle?
yeah
But i suppose you can take r = √(ab) and still get it?
Maybe?
r^2 is easy to replace just write ab I guess
yeah
for point being the midpoint of a chord is ((-s11)^3/2)/sqrt(r^2+s11)
Then it's easy innit?
Midpoint of chord is just the focus here
uhh
no?
look at the diagram
and what it's asking
oh wait
nvm he drew it wrong
latus recta yes
correct fam
so that'll give area for the triangle that's outside (EF and external point say)
and x2 because there's another one
and total area of the region bounded by the four tangents is 4x1/2x(ab) where a and b are the distances from origin to the point of intersection of the coordinate axes and tangent
I was very confused for the moment because I thought you typed x², and was wondering why that would come here. Then I realised you meant ×2
so take the total area and subtract this
what 💀
x^2
anyways
A lot of people don't do that.
lowkey cringe
basic math syntax
. feels boring to type
Then there's using LaTex
wot
man I need more people to ask doubts lately weekend syllabus been boring
$x^2$
what the hell
Opt
That
oh acha
we good?
+solved @BlindSniper (BS) @Opt
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