20 Replies
@Apu
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.btw multiple correct hai
qr code
looks interesting lemme try
yeah nvm no clue
would like to see solution
For x replace phi by pi/2-phi and use half angle properties to get x=tan(pi/4-phi/2) and similarly y=cot(phi/2). Now use tan(a+b) to get (2)
How in hell ae wwe supposed to get that replacement approach in our mind
nahh nahi aa raha bhai
im deff doing something wrong
bhai ye thrid step me kya kiya hai 💀
Which one sorry?
the one where you cancelled the terms out
what have you done there
2 sin^2 pi/4-phi/2 kaha se aaya
even the denominator
Well Pehle sin(phi) ko cos(pi/2-phi) abd similarly sin ko cos mein likh sakte hai
ha ok
Then use 1-cos(theta)=2sin²(theta/2)
And sin(x)=2sin(x/2)cos(x/2)
wth is this??
what property is this
ye to nahi yaad
oh wait
nvm
got it
sori
my bad
bit high
but wouldnt this be -2sin^2 theta/2
cuz cosA=1-2sin^A
abey yaar sori
jrgfibsdfkjv
i should sleep idk my brain is fried ;-;
thanks
ill note this down
simplify to sines and coses and substitute youll get answer
how would you take half angles in terms of x and all
or are u simplifying thje ratios and then figuring out the replacement terms?
this
ok
Yo this clear? @Phalawor
Oh yea yea thanks dude
+solved @SirLancelotDuLac
Post locked and archived successfully!
Archived by
<@964432960197632059> (964432960197632059)
Time
<t:1733645986:R>
Solved by
<@1075951732460376214> (1075951732460376214)