6 Replies
@Dexter
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.O is an intermediate
which is supposed to be out of the actual rate law
since net rxn is in O3 and O2
tyyy
how did u know
it was an intermediate
as mentioned in soln , rate of rxn is only and only from slow step also, we know the actual rxn
so rate law should be in terms of actual reactants only
intermediate O is being created and then used so it has to eliminated to get net rate law
Ohhh damnn
I see
Thanks