Small Binomial Doubt

how did it break how did (21x20 + 8 )^2024 break in 21m + 8^2024 Ques was finding remainder when 448^2024 was divided by 21
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iTeachChem Helper
@Apu
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SirLancelotDuLac
When you write the binomial expansion for this, all terms except 2024C0*8^2024 have 21 as a common factor
Gamertug
GamertugOP3mo ago
oh wiat nvm i get it each term will hav 21 except 8^2024 ye +solved @SirLancelotDuLac
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