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@Gyro Gearloose
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.where did this come from , question was asking parallel combination of Resistances
R1 = 4 +_ 0.8
R2 = 4 +- 0.4
Nope you gotta do implicit differentiation
Khan Academy
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Implicit differentiation | Advanced derivatives | AP Calculus AB | ...
Some relationships cannot be represented by an explicit function. For example, x+y=1. Implicit differentiation helps us find _dy/dx even for relationships like that. This is done using the chain rule, and viewing y as an implicit function of x. For example, according to the chain rule, the derivative of y would be 2y_(dy/dx). Created by Sal ...
why diffrnetiaon
i remeber if Z = (x^a y^b)/q^c
Then Delta Z / z = a dx /x + b dy/y + cdq/q
that does not look diffn to me so why diffn here
You took logarithm both side then differentiated in this case
oh so all error cases are diffn only?
Yes
ic ok got it
dont we apply implicit when the variables are kind of interlocked uh dependant gives some value like x^2 + y^2 = 1 ,
why we doing that here
wait how is x^2 + y^2 = 1 independant
if change x , y changes
Bhai r1,r2,req are also dependent right?
no , if we change r2 or r1 , req will change , no condition given on req
Ara bhai
Firstly ye independence wagerah matter nhi krta eitherway its true
Youre just applying chain rule with extended steps
wait lemme try diffn it
ook i got that expression by simple diffn
thx @SIMPle Potato
+solved @SIMPle Potato
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