19 Replies
@Apu
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.wow what the hell
such a bad question
huh
give me a second I'm writing
I'm not sure if this is what they want by tn but this is how the series should go
would like it if someone else took over from here
This is a sequence with difference in APs right?
Writing this is in telescoping would be $v{n}-v{n-1}=a{n}$ where $v{n}$ is nth term of sequence and $a_{n}$ is nth term of an AP.
SirLancelotDuLac
yes
can you solve it ?
I don't understand Vn -Vn-1 method
It's a quadratic sequence
cubic ig
I think its just better to use the formula for this
$T{n}=a+(n-1)d{1}+\frac{(n-1)(n-2)}{2!}d_{2}+...$
SirLancelotDuLac
Where $d{i}$ is the i-th difference. (Like $d{1}$ is the difference between terms, $d_{2}$ is difference between differences of terms and so on)
SirLancelotDuLac
how have I never seen this
+solved @SirLancelotDuLac
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