Theo's Typesafe Cult•3mo ago

One click image upload form

I want to create a one click image upload button, ideally using next JS's server actions. i would like to have a form, in which the only element is an input field that the user can upload a file to, as soon as the file is uploaded - I want the form to be submitted, and the server action to run. Currently - i am doing this like so.

function UploadImageButton({ ...otherProps }: React.ButtonHTMLAttributes<HTMLButtonElement>) {
  const { form, action, handleSubmitWithAction, resetFormAndAction } = useHookFormAction(
    uploadImageAction,
    zodResolver(uploadImageSchema),
    {
      actionProps: {},
      formProps: {},
      errorMapProps: {},
    }
  );

  return (
    <form onSubmit={handleSubmitWithAction}>
      <Button
        {...otherProps}
        className="flex flex-row items-center justify-center gap-1 relative overflow-hidden"
        size={"sm"}
      >
        {action.isPending ? (
          <StandardLoadingSpinner />
        ) : (
          <>
            Upload <ImageUp className="w-4 h-4" />
            <input
              className="opacity-0 absolute hover:cursor-pointer"
              type="file"
              onChange={(e) => {
                if (e.target.files?.[0]) e.target.closest("form")?.submit();
              }}
              onClick={(e) => {
                const element = e.target as HTMLInputElement;
                element.value = "";
              }}
              accept="image/png, image/jpeg"
            />
          </>
        )}
      </Button>
    </form>
  );
}

function UploadImageButton({ ...otherProps }: React.ButtonHTMLAttributes<HTMLButtonElement>) {
  const { form, action, handleSubmitWithAction, resetFormAndAction } = useHookFormAction(
    uploadImageAction,
    zodResolver(uploadImageSchema),
    {
      actionProps: {},
      formProps: {},
      errorMapProps: {},
    }
  );

  return (
    <form onSubmit={handleSubmitWithAction}>
      <Button
        {...otherProps}
        className="flex flex-row items-center justify-center gap-1 relative overflow-hidden"
        size={"sm"}
      >
        {action.isPending ? (
          <StandardLoadingSpinner />
        ) : (
          <>
            Upload <ImageUp className="w-4 h-4" />
            <input
              className="opacity-0 absolute hover:cursor-pointer"
              type="file"
              onChange={(e) => {
                if (e.target.files?.[0]) e.target.closest("form")?.submit();
              }}
              onClick={(e) => {
                const element = e.target as HTMLInputElement;
                element.value = "";
              }}
              accept="image/png, image/jpeg"
            />
          </>
        )}
      </Button>
    </form>
  );
}

This does not seem to be working as intended, as for one the page is refreshing when the file is uploaded (how do i do something similar to e.preventDefault using the form.submit() method to submit?) and the action is seemingly also not being hit/ran. Could anyone give any tips on how they've / would go about achieving this? Thanks.

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One click image upload form