diffrential equations error ( class 12 cbse)
isnt this wrong , isnt sinx/tanx = cosx
brainly link = https://brainly.in/question/6164199
the original question is a linear diffrentiation q
( y - sin x)dx + tanx dy
can someone show me the working thanks coz the answer in my book is logsecx/sinx
6 Replies
@Apu
Note for OP
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Yes, but the approach is correct.
(y-sin(x))dx=-tan(x)dy
So, $\frac{dy}{dx}=cos(x)-ycot(x) \newline$. This is an LDE with integrating factor $e^{\int{cot(x)dx}}=sin(x)$. Now, $y \cdot sin(x)=\int{sin(x)cos(x)}dx$
SirLancelotDuLac
wdym