Aldehyde Ketone doubt
Cant there be epoxide ring opening by base catalysed mechanism in (B) to form CH3Ch2CH(OH)CH3 and then this gives +ve iodoform?
11 Replies
@Dexter
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.O-K+ maybe hinder with the iodoform test
Achcha I see
The -OH at C1 will interefere with iodoform test also?
👍
No no, that would have given iodoform test
An OH grp connected to a carbon with atleast one hydrogen satisfied the condition
The O-K+ is the issue
But it should be methyl hydroxy C right? for +ve iodo?
See, if its a carbonyl, then it must have a CH3 group connected to the carbonyl C and if its OH group, the carbon to which that OH is connected to must have a CH3 group AND it also must have atleast one hydrogen
Ye. So instead pf ch3, we have ch2oh, the reason it won't give iodo, if I understand correctly/
Ohh yeah i was wrong Sorry, see the C1 carbon doesn't have a CH3 grp so even if it didn't have an O-K+ it still won't show iodo
Yep. Thanka a lot.
+solved @Aguilar
Post locked and archived successfully!
Archived by
<@1075951732460376214> (1075951732460376214)
Time
<t:1727661604:R>
Solved by
<@969530565177008149> (969530565177008149)