Integration graph
Is there any method by which we can know that the area is going to be zero without actually integrating (que 3)
17 Replies
@Apu
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.Just by looking at options it is clear that the area would hve been zero of the first part
The image seems to be a bit cutoff, what is the question?
Its that cos2-cos4 ke upar wla
,rotate
Oh the 1/sqrt(mod(x)) one?
Yes.
Notice x(x-6) is even about 3, (10-x)(x+4) is symmetric about 3 and (3-x) is odd about 3.
So net product is odd about 3. Given range is 3-1 to 3+1, hence algebraic wale ka area comes out to be zero.
how do you tell if something is symmetric or not
Well, it would be clear if you substitute x-3 as t. Then the polynomial function becomes odd.
ek jugaad pta hai mujhe, idk if it works always or not
wo 10-x x+4 hai uske 2 roots hai obv -4 and 10
10 and -4 ke exact bich mai 3 lie karta hai to uske abt sym
nice
we good?
Solved
+solved @SirLancelotDuLac
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