19 Replies
@Apu
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.,rotate
The ans is 1/4, here is my approach
Umm...
Well one approach would be to draw graph and determine area geometrically.
Because the graph of |x-a|+|x-b|+c is known.
Oh I'm very sorry, the {} is fractional part of x
Elsewise, your answer would be correct
man what a silly mistake 😠i didnt see this
Yeah, they should've mentioned that honestly tho.
Oh sorry they did mention that lol.
I didnt see that:aah: :aah:
Anyways now that we know it is fractional part what should be the approach
Same here 😆
Well, the -4 part doesn't matter now (Because {x+I}={x}), and then split it into parts (or draw graph)
I think we need to break it from like 0.5 to 1 then 1 to 2 maybe
Yep.
Yeah
The (1,3) wala part ka fractional part is 0 and the other two parts are linear and their fractional part varies from 1/2 to 0 linearly over (1/2,1) and (3,3.5).
So, the answer would be $2 \cdot (1/2) \cdot (1/2) \cdot (1/2)$
SirLancelotDuLac
Woah that was quick
But how did you figure out that value will be between 1/2 to 0
Actually I have the graph drawn, so I just looked at that. 😅
But at x=1/2 the value of f(x)=-1/2 and at f(x)=1, it is -1. So, the value of {f(x)} goes from 1/2 to 0. Also the function is linear over (1/2,1) and (3,3.5)
Oh i see
+solved @SirLancelotDuLac
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