Cloudflare Developers•4mo ago

URL origin rewrite using rule snippets

I'm trying to do an URL rewrite based on the HTTP status code, so basically: if example.com/something status equals 404, then keep showing the same example.com/something URL but show the content of example.ORG/something. This is the code I currently have and it's not working, it's instead doing a redirect to example.org/something and I don't want that. I want to mask that content under the first domain.

export default {
    async fetch(request) {
        const response = await fetch(request);

        if (response.status === 404) {
            const newRequest = new Request(request);

            const url = new URL(request.url);
            url.hostname = "example.ORG";

            const response = await fetch(url, newRequest);
            const newResponse = new Response(response.body, response);
            return newResponse;
        }

        return response;
    },
};

export default {
    async fetch(request) {
        const response = await fetch(request);

        if (response.status === 404) {
            const newRequest = new Request(request);

            const url = new URL(request.url);
            url.hostname = "example.ORG";

            const response = await fetch(url, newRequest);
            const newResponse = new Response(response.body, response);
            return newResponse;
        }

        return response;
    },
};

1 Reply

FocuxOP•4mo ago

Oh, the fix was not passing the newRequest to fetch. Issue solved!

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URL origin rewrite using rule snippets