quadratic
if a+b=8, ab+c+d=23, ad+bc=28 ,cd=12
then find
a+b+c+d=?
ab+cd=?
ac+bd=?
ab=?
where a,b,c,d are real
14 Replies
@Apu
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.my current approach is making two quadratics in a and d and then making cases
case 1 : both roots common
till case 1 its ok doable , problem starts with case 2: one common root helllish calc shortest method ??
till case 1 its ok doable , problem starts with case 2: one common root helllish calc shortest method ??
i found this on stack exchange but its impractical since exam mein soch pana is nearly impossible
i think trial n error is the only possible soln?
well is there any possibility this can be done by matrices. Im 11th guy so idk but a senior just took a guess about it
Any criteria given for abcd? Natural number positive only or something
abcd are real
nah idts
wht about this?
Ig the shortest way of approaching is guesstimating then
Cd=12 , list out all the possibilities and match with a+b .
Ik it says real nos but options dekh le lag rha hai integers honge (which they are)
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other than these 2 solutions, 4443 and 5362 are also possible
hnt se
Ahh...nice one.
Symmetric nature , answers ultimatelu same hi rhenge
+solved @itsav23
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