redox
In this question I was able to find out the number of transferred electrons
N- +6
Cr- (-6)
Cuz it's a disproportionation reaction, the nfactor should be:-
6*6/ 6+6 = 3
But the answer is M/6 and not M/3.
Where did I go wrong?
(I am presuming net change liya hai but then again we have a formula for disp, why not use it?)
(I am presuming net change liya hai but then again we have a formula for disp, why not use it?)
13 Replies
@Dexter
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.oh yes the same element isn't getting reduced and oxidised so it won't be an example.
Sir but in this equation for example, how will we calculate the nfactor without using the formula?
iteachchem
Transcription requested by TempestUknow
hey dude this is not a disproportionation reaction disproportionation means that the same element undergoes oxidation and reduction right but that's not what's happening over here again you have a compound made no different elements so it's either reduction or oxidation that you consider in fact even a disproportionation logic is the same you consider either oxidation reduction getting back to this point over here if you have two nitrogen atoms total number of electrons transfer is 6 so it's going to be for one mole of this whole compound 6 mole of electrons are transferred that's it so m by 6 cut up
Aakash NEET
YouTube
Balancing: Oxidation Number, Half Reaction | L3 | Redox Reactions |...
Notes: https://t.me/neetaakashdigital/7098All Lectures: Redox ReactionsL1: https://youtu.be/L359FZy7prYL2: https://youtu.be/W8dVlz7lCPAL3: https://youtu.be/e...
Check 40 min.
@itsav23
+solved @iTeachChem
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