14 Replies
@Gyro Gearloose
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.There is friction due to centripetal force
But gravity is neglected and mass of bead is not given too. Omega is constant too. How will the bead slip?
omega is not constant
alpha is
Try to make the situation at some angle Q from initial positions draw all the forces
See if you can make any equations
how to bring time into picture
m (omega)^2 r = coeff of fric * normal is one equation formed
How can we even determine normal if gravity isn't in action. We don't have any limiting value of friction here
Omega at a time t
Alpha to constant hai na eqn of motion lg jayegi
is my diagram correct?
because according to my diagram, tangential aacln ka kaam kya hai
Whole underroot mu/alpha
not my solution but mere dost ne bana liye kaafi high level aur specific visualisation thi ye to 💀
tangential force will provide the normal reaction toh ek eq toh woh banegi
second equation
yep, v= u+ at here
omega= alpha*t
Third equation
in teeno ko solve karke ans aa jana chahiye
got it thnku
+solved @itsav23 @Deleted User @Real potato
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