AOD
How can know about concavity in a period without actually plotting the graph like in the option C of 4th que
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@Apu
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f(x)=$\frac{1}{x}-\frac{1}{x^{2}}$, f''(x)=$\frac{2}{x^{3}}-\frac{6}{x^{4}}=\frac{2x-6}{x^{4}}$. Now $x^{4}$ is always positive so for x>3, function is concave up.
SirLancelotDuLac
you can separate it into 1/x and -1/x2
1/x is rectangular hyperbola 1st and 3rd quad
1/x2 is similar but no -ves (quad 1 and 2)
since we subtract 1/x2 you will have 3 and 4 quad (-1/x2)
Oh yeah. This works too.
Oh without plotting the graph?
sorry did not read xD
why is the point 3 significat, samjha nahi
ah and is this the way you do it using calc? interesting ye sab bhool gaya :P
Thanks man i got it
+solved @iTeachChem @SirLancelotDuLac
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