7 Replies
@Apu
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.maybe if you expand the bracket and take it as t it might work
let me try
u can ask me if u still have any doubt in any steps, I'll explain it
otherwise close the thread and mention me
slight correction; the integral of 1/sqrt(x^2-a^2) is cosh^-1(x/a) but I wrote cosh^-1(x)
my bad
Alright thanks
+solved @BlindSniper (BS)
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