circles
Question itself is easy imo , but very very tedious . What is the shortest method to tackle this?
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@Apu
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(Conic trauma incoming :sweaty: ) (Draw figure by finding points). Triangle ABC is isoceles so radical line cuts BC at its midpoint. So AD is perpendicular to BC. Now the circumcenter has AC as diameter so equation may be obtained.
+solved @SirLancelotDuLac
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