oxidation...redox titration
Can anyone explain me what's happening in this prob.
Like chala kya Raha hai idhar
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@Dexter
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,rotate
if its the iodine one then
meq of h2o2=meq of iodine
5* Normality = 0.508/127
normality * 5.6 = volume strength
if its 24
2M solution means 2 moles per 1000ml so 1/250 moles in 20ml
this is diluted to 400ml i.e new molarity = moles/0.4
meq of naoh = meq of hno3
25*normality of naoh = 50 * normality of hno3
i am not sure but probably n factor of hno3 here is 5 so use normality= nfactor*molarity
question 25 , pretty much the same approach. find molarity of washing soda and then equivalence concept
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+solved @hardcoreisdead
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