maxima minima

I have this function I want to find its maxima and minima , I found maxima using derivative but how I find minima
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@Apu
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Gamertug
GamertugOP8mo ago
,rotate
TeXit
TeXit8mo ago
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hardcoreisdead
hardcoreisdead8mo ago
-root2 Just use asinx+bcosx+c ka minima = c- √(a sq+ bsq) Maxima c+ √(a sq+ bsq) Otherwise use x= pi + pi/4 ( since both cos and sin are negative ull get minima)
Revita
Revita8mo ago
ek formula hota hai asinx + bcosx ka minima maxima nikalne ke liye it is + underooot(a^2 + b^2) and - of that for minima
Priyam Alok
Priyam Alok8mo ago
@Gamertug there are more solutions of $\cos x=\sin x$ so consider them too
TeXit
TeXit8mo ago
PING ME FOR CALCULAS PROBLEMS
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Revita
Revita8mo ago
ye sahi chiz hai
TeXit
TeXit8mo ago
Revita
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Lindane
Lindane8mo ago
See sinx=cosx is also gonna happen at 5π/4 par so it's also a root of dy/dx put that too dy/dx gives both roots
iTeachChem
iTeachChem8mo ago
we good?
Gamertug
GamertugOP8mo ago
+solved @hardcoreisdead @Priyam Alok @Lindane
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