I
iTeachChemβ€’6mo ago
Revita

ELECTROCHEMISTRY

IMG
No description
33 Replies
iTeachChem Helper
iTeachChem Helperβ€’6mo ago
@Dexter
iTeachChem Helper
iTeachChem Helperβ€’6mo ago
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.
𝑻𝒉𝒆 π‘Ίπ’Œπ’š
@Revita karle bhai tera doubt hue
Revita
RevitaOPβ€’6mo ago
Attempt is as such: in my solution i took Eo = -1.35V
iTeachChem
iTeachChemβ€’6mo ago
Thanks for helping out, appreciate it :) Question please :)
Revita
RevitaOPβ€’6mo ago
Yes just a minute pls
Cakey Bot
Cakey Botβ€’6mo ago
iteachchem
Transcription requested by Revita
Hello, you don't tag me that Dexter Tang basically tags all people who have mentioned that they want help in chemistry, want to help out with chemistry.
Cakey Bot
Cakey Botβ€’6mo ago
iteachchem
Transcription requested by Revita
Yeah, let's do that like that.
Revita
RevitaOPβ€’6mo ago
sorry that was the wrong ques
Revita
RevitaOPβ€’6mo ago
No description
Revita
RevitaOPβ€’6mo ago
so -ve nhi hota?
iTeachChem
iTeachChemβ€’6mo ago
Why would it be :D. It likes being reduced. Oxidation potential -ve hoga. Anyway. You focus on solving the question. Ignore the solution as such. Attempt kariye from scratch.
Revita
RevitaOPβ€’6mo ago
Alr thank you sir Ha i was also thinking tht since Cl ka reduction spontaneous hota hai n
Ishizora
Ishizoraβ€’6mo ago
actually it's not a typo as when writing the notation for standard potential of a half cell which is being oxidised the electrode taken is written first whereas idhar par reduction ho raha h cl ka due to it having less srp so idhar par uska standard reduction potential lena hoga which is opposite in sign of standard oxidation potential had it been standard reduction potential it would've been written as E not cl-/cl2/pt = 1.35
iTeachChem
iTeachChemβ€’6mo ago
@Revita
iTeachChem
iTeachChemβ€’6mo ago
https://goldbook.iupac.org/terms/view/G02590 source for this. basically you write the inert electrode first, then phase boundary then gas and then phase boundary then ion. it may look confusing but both the ones mentioned here are oxidation parts (for hydrogen and chlorine) if Pt is on the right that would be the cathode, good call @Ishizora
IUPAC - gas sensing electrode (G02590)
The IUPAC Compendium of Chemical Terminology
iTeachChem
iTeachChemβ€’6mo ago
btw, looked around, this is not a crucial part of jee prep (knowing the iupac e cell notation). in ncert is just says 'convention' since ye cathode pe tha, you know it is reduction, baaki solution you can figure out from there.
Revita
RevitaOPβ€’6mo ago
could you explain in hindi pls i didnt understand
Ishizora
Ishizoraβ€’6mo ago
Glad to help out
:)
:)
Revita
RevitaOPβ€’6mo ago
hmm hamko gas boundary and bubbling wo sb nhi sikhaya hai since you said ncert mai nhi hai
iTeachChem
iTeachChemβ€’6mo ago
Yea Ditch. But this is how gas electrodes are represented phase boundaries work
𝑻𝒉𝒆 π‘Ίπ’Œπ’š
onekiss_bruh inert electrode ke ka concept sikh le left me hoga to anode - oxidation inert electrode ke bagal me gas hota ha
iTeachChem
iTeachChemβ€’6mo ago
+solved @𝑻𝒉𝒆 π‘Ίπ’Œπ’š @Ishizora
iTeachChem Helper
iTeachChem Helperβ€’6mo ago
Post locked and archived successfully!
Archived by
<@1035556259417571408> (1035556259417571408)
Time
<t:1724409671:R>
Solved by
<@757265721519767563> (757265721519767563), <@928992127868866590> (928992127868866590)

Did you find this page helpful?