ELectric Charges

For this Question I tried Kq1q2/r^2 = -K(q1 + 1)(q2 +2) / r^2 the condition Came -q1q2 = q1 + q2 but non of the options satisfy
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@Gyro Gearloose
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Gamertug
GamertugOP8mo ago
force same but opp dircn so F = -F
Ishizora
Ishizora8mo ago
-q1q2 = ( q1 +1 ) ( q2 + 1 ) q1q2 + q1 + q2 + 1 = -q1q2 2q1q2 + q1 + q2 + 1 = 0 satisfies option c nope you can't just apply that directly carefully looking at the question it says initially forces where attractive which mean they had opposite charges Later the forces b/w them became repulsive which means that they now had same sign applying what i've mentioned above you'll get your answer as option c btw it can be done by simple elimation as well at first charges should of opposite sign to be attractive it is given that mag remains same so just check options by multipying them before adding 1 and after adding one if they remain same then that will be your answer which in this case is c
Gamertug
GamertugOP8mo ago
ooh i forgot 1 isnt the thing u did also F = -F
Ishizora
Ishizora8mo ago
it is mb
Gamertug
GamertugOP8mo ago
+solved @Ishizora
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