13 Replies
@Gyro Gearloose
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.my bad pinged it to phy one
This is very Common question in every book
I do have the long ways but there must be some short methods right
Or am I just missing smthing
@Apu
There are different methods, but the one which I prefer was for I, take a point such that the point lies on line and that point, reflection of A about the line and B are on same line/
I figured out S and P and R
For s just used products of slopes = -1
For P took reflection, made line and point of intersection
Well, if you want solution for Q: The minimum value of mod(aq-bq) is 0. Now, how can we achieve this 0? If we consider the perpendicular bisector of line AB and find its intersection with given line, we are done.
i found the mid pt of ab as 6,6 and then its slope which is -1. the slope of ab * slope of midpt to q =-1 therefore x=y and easily it comes out to be -2,-2. thanx a lot. pls review this method and then ill close the thread @SirLancelotDuLac
Yep, this is absolutely correct.
aight, thanx
+solved @SirLancelotDuLac
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