Current Electricity
in this Question using R = rho L/A and V = Edl
We Get I = E x A x K
E is alr in milli now we convert units to meter so area will be 25pi 10^-8 and conductivity is 10^7 , the ans is 5 am i missing something? where did 10^-1 go
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@Gyro Gearloose
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bhai its correct only right
10 x 10^-3 x 25 x 10^-8 x 5 x 10^7 x pi
125pi x 10 ^-3
they're asking the answer in milli ampere
wait forgot 10 ye its right
+solved @trin
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