circular motion with pendulum
16th q from hcv, answer key says C, but im not getting how.. personally i think its B, can someone explain how it could be C (if it is)
cus according to me the tension will be mg/cos at that point
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@Gyro Gearloose
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Tension is MgCQ+mv^2/r i hve solved from non intertial frame ground frame se bhi same eqn aayegi as u can see jab velocity zero hogi tab hi T=mgcosq hoga
Or simple pendulum me velocity sirf extreme point pr instantaneously zero hoti h
extremes pe velocity will be zero , only thing contributing to tension will be component of mg towards tension, uske baad mgsintheta aage leke jayega and then same cycle repeats
haan got it, i had misunderstanding where i took component of velocity parallel to ground instead of direction of velocity which is why i said mg/cos, mbmb
+solved @hardcoreisdead @Real potato
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