phy
Question 12
My approach was taking component of g towards op , which comes out to be g/2 and the dist op = r/2
For oq , accn is g and path length 2r
Using 3rd eqn of motion we find velocity and then ratio comes out to be 1/2root2
9 Replies
@Gyro Gearloose
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.ratio of OQ to OP will be 2:1
triangle opq is in semicircle so angle P is 90 degree
u can apply cos 60 and find ratio of lengths and go ahead
acc to me ur only mistake was assuming distance op as r/2
i got ans as C
Whts the answer?
Im getting 1/2
V1 is root rg and v2 is 2 root rg
same here getting 1/2
using conservation of mechanical energy
1/2
why is my method wrong
OP r nahi hoga? u have written it as r/2
Oh , I directly took component of r there r cos theta but it wasn't a right triangle.
Baaki approach shi hai , taking component of g and all
Thanx
+solved @vj_25
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