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@Dexter
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.also does this data check out
Fraction lelo bhai or 100 se krdo multiply
matlab?
with d orbitals i dont think u can do that
my sir taught only comparison of s character by def not by percentage or smthing
closer the bond pair to the central atom more is the s character
Yes ye logic bhi thik h
Kyuki jis bond ka s character zyada hota hai uski EN bhi zyada hoti h
Thats why bond pair Central atom ki taraf shift hota h
yeahh
easy language me
sp3 hai 3 parts of p and 1 part of s so thats
75:25
and 25 percent is the s character
ye this is what i learnt
can i do the same for sp3d and further
1:3:1 s p d
yes yes
1 part of s,3 of p and 1 of d
60% p ?
c?
Yes
But
option B
D ke liye it's not actually used
Sp,sp2,sp3 ke liye it's used
why?
no of unpaired electrons is 2, and then u apply the magnetic moment formula
1s2 2s2 2p1
root of n(n+2)
or do i use the mot one
uss se bhi yhi hoga
MOT apply
no bro ur supposed to calc for mot one, for boron molecule
1s2 1s*2 2s1
not for boron atom
oh my bad
Its B2 molecule
all good 🙏
then what is the percentage of p character in the equatorial orbital of pcl5
60%
But commonly asked questions ki baat kr rha tha 😄
D wale kam ate hai
ye dont ask for sp3d and all but if they do that method is right (% wala)
Sp,sp2,sp3 ka yaad krlo
66
50,25,33.33
sp3d is sp2 + pd
Equatorial and axial respectively
60
Just googled
66.67 is the answer
How?
ek sec how did u break this?
Ratne ka hai
baaki saara bhi bata do
But vo hai to hybrid orbital
Different kyu treat kr rhe hai axial equivtoral ko
ratne wala portion
sp3d3 me bhi hai, dunno the the parts but axial has more s character
(it's in Bent's rule)
jd lee mein dia hai?
@hardcoreisdead bro whats ur source for qs
fiitjee modules and reference books
Page 74-75 effect of electronegativity
chemical bonding mein right ?
Yes
aight , thanx
yeh bhi bata do
B, C?
sirf c hai
why not d ??
b mein toh ek lone pair hai na
f will have lone pairs na
Back bonding
+solved @_masterchef @g-sus @Deleted User @Real potato
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BTW, @g-sus @hardcoreisdead
these dont really exist for pcl5, sf6, if7.
PCL5: https://chemistry.stackexchange.com/questions/18427/why-does-f-replace-the-axial-bond-in-pcl5/18544#18544
SF6: https://chemistry.stackexchange.com/questions/24671/why-does-stannous-chloride-occur-despite-the-octet-rule/24675#24675
IF7: https://chemistry.stackexchange.com/questions/28692/pbp-vs-tbp-geometry/29120#29120
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