Please help me how to do this?

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iTeachChem Helper
@Apu
iTeachChem Helper
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Deleted User
Deleted User6mo ago
answer 3 hai (i didnt use maths, but python) @Cheetahhh
Cheetahhh
CheetahhhOP6mo ago
it came in an aptitude test so I wanted to know how touse, I mean I used binomial expanison, but I didn't knew uske baad what should I do like 2000^1000 = (13*153 + 11)^1000 , now binomial expansion leaves me, to (11)^1000 %13. I mean yeah I can continue like further, like 121^500 = 4^500 = 2^1000 to.. then futher expanding.. eventually I will reach.. but isn't it too long for one question? I mean questions are like solve 25 questions in 20m mins.. I can't give 5 mins to one question
¹¹⁷sos
¹¹⁷sos6mo ago
You can write 11 as 13-2 Then it's (-2)^1000 You can write this as 16(2)^996 Now I did that cause 996 is divisible by 6 and is 1666 Hence it is 16(64)^166 Write 64 as 65-1 as 65 is a multiple of 13 Hence we get 16(135-1)^1000 Then we get 16 phir remainder aagaya 3
iTeachChem
iTeachChem6mo ago
+solved @¹¹⁷sos
iTeachChem Helper
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