MEC
how to derive it mathematically and on what factors does the radius of path depends? If the projection kinetic energy is same?
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@Gyro Gearloose
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Yeah
i know it is theoretically correct but im unable to prove it mathematically
see
kinetic energy = 1/2 mv^2
now v= root 2ke/m
now qbv= mv^2/r
when you find r and put value of v as the before eq
you'll get that r is directly proportional to root m/q
and with the given info in the q
when you find ratio of the radiis its coming 1:1
so they've same radius
Yo thanks i got it
pls mark the doubt as solved :)
+solved @trin
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