kinetics conceptual
Here it's said that the reaction is 1/4th and 1/16th completed respectively.. Now for 1st order reaction, in the log (A°/At), At is the concentration of reactant remaining right? So shouldn't the At portion in both be $(a-frac{a/4})$ and $( b-frac{b/16})$ ?
(In the second one they actually did it, but messed up the fraction)
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@Dexter
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the q says 1/16 of initial conc. your statement says 1/16th completed. these are different things. what do you think?
There is a direct way to do this btw, 1/4 is x, so 1/2 is x/2 (time taken)
1/16 is x/2 into 4, ie 2x = 40 min.
Yeah, alright.. My bad. I wanted to write 1/16 reduced... So remaining is 15/16 right? So why are we considering it ias a/16 instead of 15a/16
And I too had done it with the short cuts , the multiple of t50%s , and got 40 ... And after that I had a confusion regarding the concept
Please read the question again
Cool!
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