MOTION IN !D
I am getting A but with a minor coordinate difference.
In the v vs t graph in place of 4 + 2root6, I am getting 6 + 2root6.
I think i have a little confusion in taking time intervals on the graph.
16 Replies
@Gyro Gearloose
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.did you figure this one out?
um no sir
@Gyro Gearloose any inputs?
iteachchem
Transcription requested by Messier 87 (M87)
Do you try looking it up online? I've told you how to look up a question on Google, right, image search vs image search. You can check it out on the pinned post of the doubt section. Try that as well.
Its quite simple na its simple motion under gravity with initial velocity 40ms after 2 seconds?
When is the accn hitting values in roots? Acc to me accn 10,-10 ya 2 ki values mein hi ho sakti hai . I got confused with these accn values in roots
Looking solely at the vt graph ig it should be option a
Graph hits peak at 40m/s after which it deaccelarates under gravity till it hits zero and then attain momentarily rest. Aftev which it velocity increases in negative dirn
In other graphs velocity doens't become zero so ig option a ?
@Gaurav what's the answer ?
yes its a but i didnt ask for the answer
i made graph by myself without hit and trial but i am getting difference in a coordinate as i have written above
Oh , I simply used logic , no calcs. Also ig the a t graph is wrong
the symmetry is correct but the values seem to be incorrect to me
Same
Toppr Ask
A diwali rocket moves vertically up with a constant acceleration a_...
Click here👆to get an answer to your question ✍️ a diwali rocket moves vertically up with a constant acceleration a1 203 ms2 after
closing this out guys :D
please check questions like this on google once (reverse image search :)
+fsolved
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