I@Dexter
INote for OP
+solved @user1 @user2...
Ican you make an attempt please?
Ihint:
moles of electrons involved in oxidation = moles of electrons involved in reduction
sum of both will be the moles of electrons that interact with I2.
moles of electrons involved in oxidation = moles of electrons involved in reduction
sum of both will be the moles of electrons that interact with I2.
Ii have solved a similar q in the videos btw if you wanna see it (redox reactions)
IBUT
n factor = moles of iodine/ moles of electrons involved in EITHER in reduction or oxidation
n factor = moles of iodine/ moles of electrons involved in EITHER in reduction or oxidation
Bi did
BI used Comproportionation rxn, am i right?
BAHHH thats where i made mistake
IYouTubeAakash NEET
Notes: https://t.me/neetaakashdigital/7098
All Lectures: Redox Reactions
L1: https://youtu.be/L359FZy7prY
L2: https://youtu.be/W8dVlz7lCPA
L3: https://youtu.be/eGACAX7e6_o
L4: https://youtu.be/eXtBT1Wt7Qk
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All Lectures: Redox Reactions
L1: https://youtu.be/L359FZy7prY
L2: https://youtu.be/W8dVlz7lCPA
L3: https://youtu.be/eGACAX7e6_o
L4: https://youtu.be/eXtBT1Wt7Qk
Subscribe to us: https://www.youtube.com/channel/UCAPDuc6Kfpe1mKjMX367qmA?sub_confirmation=1Join our Telegram Channel Now: https://t.me/n...Ifound the video
Bi dont understand hindi sir, but sure will give it a try thanks sir.
Iawt okok
Isee if the slides make sense anyway
Ithis timestamp
Iyou get 5/3
Iwait wait the n factor of I2 is 5/3
Inot of KI
BKI too right?
Bwhy not KI?
ICos its oxidation number changes by 1
IPer mole of KI
ISo n factor is 1
IClo3- n factor is 5
BOh damn ok i get it now.
B+solved @iTeachChem
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@1204419151792447538 (1204419151792447538)
Time
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@1035556259417571408 (1035556259417571408)