straight lines 2
using family of straight lines
L1+kL2=0
we get (3+k)x-y(4-k)+6+2k=0
given that line is parallel to 2x-y+3=0 therefore req line must be of the form 2x-3y+C= 0 where c is a constant.
i compared the coeffs directly but couldnt get the answer, why?
19 Replies
@Apu
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.Point of intersection niklo parallel line se slope uthao
sirf slope equate karne se bhi kaam ho sakta hai but why is my approach wrong
Ye 2x-3y+c kaha se le aye
Dono line parallel hai to coefficient ka ratio equal hoga
not sure doing with family of lines would help you , you are adding more variables ?
Its a direct question fam of lines will make it even longer lol
also it just says its parrallel to y = 2x + 3
so it would be more of a form of : y = 2x + C
your "must be of the form " doesnt have the same slope ,
check
my bad i added the 3 , but i intended your eqn only
y=2x+c wali
yeah that should work now
lemme try
yeah works
sick method 🔥 imma keep it in mind
actually faster ngl
huh mera kaise ni aaya fir
3+k must be =2
4-k must be =1
maybe i did an oopsie while doing , lemme write it now
brb
kk
abey ha yaar nhi aya
not sure what i did in mind
wait nvm
ans is 5/3=k
yeah
does it give -4 as c?
should i think, conceptually it sounds good
calculation sucks tho
this gives 2 values of k and c is 6+2k so cant really say
calc aasan karne ke lie hi toh yeh method lia hai , idk where does this lack tho
Yo i got it
The ratio of coeffs will be equal and not the coefficients exactly , which is just equating the slope
@Weirdo
we good?
+solved @Weirdo @Real potato
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