I
iTeachChem•7mo ago
Gogeta

motion in a straight line

No description
22 Replies
Gogeta
GogetaOP•7mo ago
@trin
iTeachChem Helper
iTeachChem Helper•7mo ago
@Gyro Gearloose
iTeachChem Helper
iTeachChem Helper•7mo ago
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.
Gogeta
GogetaOP•7mo ago
why is discplacement in 3rd second 0 and why do we need to multiply X with 2 to find distance
BroGotNoQuotes
BroGotNoQuotes•7mo ago
@Gogeta the formula used here is Snth = u + a/2(2n-1) where n here is the time, it gives you the displacement travelled in that second only. so while u use this formula u will see disp = 0.
Gogeta
GogetaOP•7mo ago
so everytime i use this formula i shud know ki displacement is 0 na ?
BroGotNoQuotes
BroGotNoQuotes•7mo ago
I dont get you..
Gogeta
GogetaOP•7mo ago
everytime i use the Snth formula is displacement 0
BroGotNoQuotes
BroGotNoQuotes•7mo ago
nope here accelaration is minus
Gogeta
GogetaOP•7mo ago
yep so the particle moves backwards, so the displacementtravelled front when it goes opposite direction it gets subtracted hence 0 ?
BroGotNoQuotes
BroGotNoQuotes•7mo ago
i dont get what hes sayin
trin
trin•7mo ago
ill explain wait
Gogeta
GogetaOP•7mo ago
🫡
BroGotNoQuotes
BroGotNoQuotes•7mo ago
alr trin will tc
Gogeta
GogetaOP•7mo ago
its a video sorry i shud have told u
BroGotNoQuotes
BroGotNoQuotes•7mo ago
ahh ok ok np bhai
trin
trin•7mo ago
bhai basically in the video he said, disp bw 2 and 3 second is zero because its going and coming back so displacement is 0
Gogeta
GogetaOP•7mo ago
yeah whyd he multiply distance w 2
trin
trin•7mo ago
always displacement is 0 because between 2 seconds the particle is travelling back and forth where?
Gogeta
GogetaOP•7mo ago
i wish i could send the pic but i gotta open a new post again
trin
trin•7mo ago
um just dm
Gogeta
GogetaOP•7mo ago
ok

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