alcohol substitution
If this is a 1 degree alcohol and Iodine anion is strong Nucleophile, then it should go through SN2 and after water leaves, the Iodine should immediately make bond with carbon, and positive charge on carbon should not form after water leaves, and intermediates don't form in SN2.... So why does the rate of rxn even matter here?
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@Dexter
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.How to solve this is clear to me, but it's not connecting to what i wrote above
Tldr. Sn1, benzylic carbocation forms :)
Yeah benzyl carbocation is stable
So it will favour Sn1
Alright i get it now thnx
I was just memorizing primary sec tertiary, but stability is the real stuff alright got it
+solved @iTeachChem
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