Atomic structure
(just lmk what ans u guys get, with steps pls)
Calculate the wavelength of first line of Lyman series of ten times
ionised sodium atom (Z = 11) and compare with the wavelength of first
line of Balmer series of H atom.
20 Replies
@Dexter
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.can i get a dpp on this chapter please?
something useful for let's class 11
talking bout byjus
i can't get that anymore bcoz
i have already used it a lot so they want me to register now
iteachchem
Transcription requested by Annika - jee aspirant 2029
Hey, do you mean like 10 questions to do every day? Is that what you mean by DPP? If you're talking about questions in general, the Byju's app is free. I've recently done some practice sessions on it. You can check those out on YouTube. If that's useful to you, you can check that out. And yeah, that's the extent of the free stuff that I know of. Yeah, nobody's going to do this over, so this is what I can help you with.
iteachchem
Transcription requested by Annika - jee aspirant 2029
Hi, can you share maybe you're working here? That would be really cool and what is your doubt? Do you just want to know how to solve it? I didn't follow your question.
and yes bhaiya that want means dpp like a set of question papers on this topic
i haven't joined nay coaching yet it will be from nxt yr looking forward for help
Lol its free. The practice bits.
The videos are paid, yea.
There is also examside
Decent interface and has massive repo of pyqs
Sarthaks is not that good the interface but good questions plus solutions.
well you don't get me they are asking me to register for free only but ya registration for further use of the app and i am avoiding it bcoz of the useless phone calls but anyways i'llmanage from other website
thatnks for cooperation
Ah. Right yea you will have to provide a phone number. Yea.
i worked it out and got 10 angstrom as the wavelength for sodium, i got the ratio as 1:653.4
when i search up the first part of the q on google, it shows 10 angstrom
this is the working i found on the internet, isnt this wrong since u have to take Z^2 for sodium (and hence take 121 instead of the 11 that they have taken) or am i missing smthing
but this is the ans in the answer key
True 121 hona chahiye.
Will solve kal if no one else picks it up by then :)
correct 1 nm hi hai answer for Na
and 654.54 nm for H
ignore this 'solution' jo aapne kiya hai sahi hai
generally, if the solution does not have upvotes on the toppr site, be vary :)
i solved it from p bahadur book and even there the soln was the same as that of topper site
which is why i doubted myself xd
books me errors hote hain, good you posted here.
thank uu
+solved @iTeachChem
Post locked and archived successfully!
Archived by
<@925057461893865474> (925057461893865474)
Time
<t:1721531981:R>
Solved by
<@1035556259417571408> (1035556259417571408)