mole concept
in 100g - 35g of hcl is there in the solution
so 35/v= 1.46 g/ml
35/1.46= v
which gives me 23.97 ml.
1 mole - 36.5g
that means 35/36.5 = .958 moles
molarity = .958*1000/23.97ml = 40M is wht im getting
but ans is 14M
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@Dexter
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.100gm soln has 35gm of HCl
density is 1.46g/ml , i.e 100ml solution weighs 146gm
Therefore 100gm soln has 100*100/146 ml volume =
68.49 ml
35gm HCl in 68.49 ml
I.e 0.95 moles per 68.49 ml
Or 0.95 moles per 68.49/1000 Litre
0.95/(68.49/1000) comes out to be nearly 14
My approach has a lot of calculation, anyone with a better approach pls reply
Nicely done. If you take the basis to be 1 l solution, the number of moles in it would be the molarity itself.
Since you have the density, mass of 1 l solution would be 1460 g.
Since 100 g solution has 35 g HCl, 1460 g soln would have 1460 x 0.35 g HCl (unitary method)
Moles of HCl would be approx 14 in 1 L solution which is the molarity.
Moles of HCl would be approx 14 in 1 L solution which is the molarity.
yea pretty much going by the basic definations would be easiest, 35% sol of hcl would imply in a quantiy of 100gm solution,we have 35gm hcl by mass. so,
1.) step 1:-mole of hcl would be 35/(36.5), lets say this quantity is "n"
2.) step 2:- volume of solution would be calculated through the density, d=m/v so v=m/d=100/(1.46) ml (denoted by v)
3.) step 3:- molarity=moles of solute/volume of soln(in L) = (n/v)*1000 (for L conversion).
this would give you a value of ~14M
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