Redox Reactions

Pls help in 2nd step not able to understand
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14 Replies
Deleted User
Deleted UserOP7mo ago
In this step how do the charges get balanced?? this is the 2nd step above one is the q
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@Dexter
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Real potato
Real potato7mo ago
They hve used the n-factor method of balancing the rxn
Deleted User
Deleted UserOP7mo ago
wht?? oh n fac ok will try one sec it shd become 2cr2O7 right?
Real potato
Real potato7mo ago
Yes
Deleted User
Deleted UserOP7mo ago
he hasnt told that im not able to understand how does the charges on the left become equal to right when added 8H+
Real potato
Real potato7mo ago
2 se divide kri hai rxn 8H+ dono side ka charge balance krne ke lie hi likhe hai
Deleted User
Deleted UserOP7mo ago
sorry i dnt understand hindi
Real potato
Real potato7mo ago
They hve divided the reaction by 2 the initial rxn will be 2Cr2o7+6SO3 8H+ are added for that purpose only so as to balance the charges on both the sides
Deleted User
Deleted UserOP7mo ago
Ohhh danggg
Real potato
Real potato7mo ago
yes
Deleted User
Deleted UserOP7mo ago
thxx +solved @Real potato
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