12 Replies
@Gyro Gearloose
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.I figured out the 1st part
At t=mg/5 A will loose contact and at t=2mg/5 B will loose contact
Confused with the second part
a=(5t- mg)/m= dv/dt, mass a losing contact at t= 2 and and b at t=4. integrate dv= (5t-mg)/m*dt from t=2 to t=4 and LHS from v=0 to V= required
how do u derive the expression for a here ?
a= net force/ mass na, net F= 5t- mg
why are u subtracting mg in net F
@lmaodedXD
huh mg kyun nahi hatayenge, FBD banao upar tension neeche mg
oh right my bad
aah yeh question maine kiya tha last year
tricky hai
@lmaodedXD bhai isme ek block pehle chalta hai fir thode der baad dusra block chalta hai they dont come in motion together
nah it was ez
yep theres a time diff
+solved @lmaodedXD
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