I@Gyro Gearloose
INote for OP
+solved @user1 @user2...
CI figured out the 1st part
At t=mg/5 A will loose contact and at t=2mg/5 B will loose contact
At t=mg/5 A will loose contact and at t=2mg/5 B will loose contact
CConfused with the second part
La=(5t- mg)/m= dv/dt, mass a losing contact at t= 2 and and b at t=4. integrate dv= (5t-mg)/m*dt from t=2 to t=4 and LHS from v=0 to V= required
Chow do u derive the expression for a here ?
La= net force/ mass na, net F= 5t- mg
Cwhy are u subtracting mg in net F
C@lmaodedXD
Lhuh mg kyun nahi hatayenge, FBD banao upar tension neeche mg
Coh right my bad
Baah yeh question maine kiya tha last year
Btricky hai
B@lmaodedXD bhai isme ek block pehle chalta hai fir thode der baad dusra block chalta hai they dont come in motion together
Cnah it was ez
Cyep theres a time diff
C+solved @lmaodedXD
IPost locked and archived successfully!
Archived by
@741159941934415883 (741159941934415883)
Time
July 14, 2024
Solved by
@1034231350141653132 (1034231350141653132)