basic rule in matrix

Just want to know the reason behind the highlighted step .. Like if the squaring is there so why isn't it P^-2A^2P^2 ?
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@Apu
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πrate
πrate7mo ago
(P^-1AP)^2 = (P^-1AP)(P^-1AP) =(P^-1A^2P) The P outside bracket in the first highlight seems like a typo
Say_miracle_shadow
Say_miracle_shadowOP7mo ago
Oh yes Could you please elaborate this step like why only ...A^2.. not P^-2A^2P^2 ?
πrate
πrate7mo ago
(AB)^2 = ABAB and not A^2B^2 Matrix multiplication is not commutative
Say_miracle_shadow
Say_miracle_shadowOP7mo ago
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πrate
πrate7mo ago
yes friend just remove the brackets now P will be multiplied with P^-1, i.e. identity matrix hence A will be multiplied by A, A^2 P^-1 on the left and P on the right remain as is just like Bs are not multiplied together P and P-1 wont be you’re not allowed to move anything
Say_miracle_shadow
Say_miracle_shadowOP7mo ago
So AA = A^2 But (AB)^2= ABAB Is this correct ?
πrate
πrate7mo ago
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πrate
πrate7mo ago
yes correct
Say_miracle_shadow
Say_miracle_shadowOP7mo ago
Okay 👍
πrate
πrate7mo ago
that’s how you multiply
Say_miracle_shadow
Say_miracle_shadowOP7mo ago
Please check this one@πrate
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πrate
πrate7mo ago
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Say_miracle_shadow
Say_miracle_shadowOP7mo ago
Okay .. Understood @πrate
Say_miracle_shadow
Say_miracle_shadowOP7mo ago
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Say_miracle_shadow
Say_miracle_shadowOP7mo ago
+ solved @πrate
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