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@Gyro Gearloose
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hint: time taken does not depend on str of field :) strengh increases, distance inc and velocity inc :D
(π/2mqB) + (π/2mqB) = π/mqB
JUST reuqired velocity hai right, to cross the first field region just riquired ka matlab assume karo ki ek quadrant of a circle travel karega jiska radius will be W, kyunki agar isse kam hoga toh usse pehle hi ghoom jayega,
matlab time taken for this = 1/4 of the time period 1
now jab ye dusre field mein enter karega, kyunki uski strength twice hai, the radius of trajectory will be halved ( r= mv/qB), toh ye ek semicircle travel kar lega,
time for this = 1/2 of time period 2
it does sir.... time period= 2piM/qB
it is independent of velocity
also the magnitude of velocity (speed) remains constant throughout the motion
it doesnt no, distance also increases?
sir magnetic force always acts perpendicular to resultant velocity, so it's actually the centripetal force so we can write
mv^2/r = qVB
we get r= mv/qB, time period= 2pir/ V, = 2pim/qB
i'm not able to understand aapka distance se kya matlab hai
distance of the thingy travelled inside the field
my physics is rusty, will have to read up on it, will take your word for it for now :)
but i figured that the time wil be the same in both
and will just add up
accha aap time taken to cross bol rahe the
i thought time period of the circular motion
my bad 😅
ji. time spent hi poccha sawal me isiliye was talking about that. my b shouldve been clear :)
Yeahhhh makes sense
Sahi hai
+solved @iTeachChem @lmaodedXD @PeterGriffinItis kitne opposite usernames h dono ke
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